Question

2. The position of an object moving along x-axis is given by x = a + bt2, where a = 8.5 m and b = 2.5 m/s2 and t is measured in seconds. What is its velocity between t = 0s and t = 2s. What is the average velocity of the object between t = 2 s and t = 4 s?

Answer 1

Answer:

x = a + bt^2

v = 2bt

Velocity at t = 0 is 0

Velocity at t = 2s is = 2*2.5*2 = 10 m/s

At t = 2s

x = 8.5 + 2.5*2^2

x = 18.5m

At t = 4s

x = 8.5 + 2.5*4^2

x = 48.5m

Average velocity = (48.5 - 18.5) / 2 = 18m/s

Explanation:

i think it will help you