Question

(-2) the power of -3 × (-2) the power of -4 × (-2) the power of 8 =​

Answer 1

Answer:

$({ - 2})^{ - 3} \times ( - 2)^{ - 4} \times ( - 2)^{8} \\ bases \: are \: same \: so \: it \: will \: be \: added \\ - 3 +( - 4 )+ 8 \\ - 7 + 8 \\ 1 \\ ( - 2)^{1} \\( - 2) \\ \\ hope \: it \: helps \: u................$

Answer 2

-2^-3×-2^-4×-2^8

=-2^-3+(-4) +8

= -2^-3-4+8

= -2^-7+8

= -2^1

= -2

Note: (a^n+a^m=a^n+m)