Question

x3-x2-14x+24 use factor theorem
​

Answer 1

Factorise x^3-x^2-14x+24 by using factor theorem is:

p(x) = (x - 2)(x - 3)(x + 4)

Solution:

Given polynomial is:

Let,

Factor theorem:

If the remainder f(r) = R = 0, then (x − r) is a factor of f(x)

Therefore,

Substitute x = 2 in p(x)

Therefore, x - 2 is factor of p(x)

Substitute x = 3 in p(x)

Thus, x - 3 is a factor of p(x)

Substitute x = -4 in p(x)

Thus, x + 4 is a factor of p(x)

Thus the factored form is:

p(x) = (x - 2)(x - 3)(x + 4)

Learn more about this topic

Factorize using factor theorem : x^3-6x ^2+3x+10

brainly.in/question/3946956

Using factor theorem show that (x-y) is a factor of x(y² -z² ) +y(z²-x² )+ z(x²-y²)