2. The sets of mathematics, physics and chemistry books have to be stacked in such a way that all
the books are stored topic wise. The number of mathematics, physics and chemistry books are
14, 18 and 22. Determine the number of stacks of each books provided books are of same
thickness.
Answers
Answer:
no.of books of each subject
192, 240 ,168
So in these type of question we have to find HCF hence its hcf is 24
Now divide it with each no.
8,10,7
Hence ther should be 8 books of physics 10 chemistry and 7 of maths so in each stack there will be (8+10+7) = 25 books
and no. of stack=total book /book in each stack
no. of stack = 24 stacks
Answer:
Three sets of physics chemistry and mathematics books have to be stacked.
Bur all the books are stored topic wise and the number of books in each stack is same.
Number of Physics books = 192
Number of Chemistry books = 240
Number of Mathematics books = 168
We will calculate the Highest Common Factor (HCF) of the numbers.
Factors of 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3
Factors of 240 = 2 × 2 × 2 × 2 × 3 × 5
Factors of 168 = 2 × 2 × 2 × 3 × 7
Common factors = 2 × 2 × 2 × 3
HCF = 24
In each stack there are 24 books. Therefore, the number of stack of each subject would be
No. of stacks of Physics books = {192}{24}
= 8
No. of stacks of Chemistry books = {240}/{24}
= 10
No. of stacks of Mathematics books = {168}/{24}
= 7
The number of stacks of physics = 8, Chemistry = 10 and mathematics = 7