Question

2. The solubility of common salt in water is 36 g per 100 g of water at 20 °C. a. If 30 g of common salt dissolves in 100 g of water, what is the mass of the salt solution formed? b. What is the maximum mass of common salt which will dissolve in 20 g of water at 20°C? C. If 50 g of common salt is added to 150 g of water at 20°C, how many grams of common salt will remain undissolved in the water? d. What kind of solution is formed when 18 g of common salt dissolves in 50 g of water at 20 °C? Common salt can dissolve in water but not in alcohol. What does this tell us about the solubility of a substance?​

Answer 1

Answer:  Solubility is the amount of solute added in a given amount of solvent to attain saturation. Hence, in the given solution, for saturation, 36−20=16g of salt is required to be added.

Explanation:

Answer 2

I=II<III

Explanation:

H2O X 14g K2CrO7

100g H2O = 4.9 g

The amount of solute required to reach saturation in a given amount of solvent is referred to as solubility. As a result, 3620=16g of salt must be added to the given solution to achieve saturation. This indicates that at 20 degrees Celsius, 36.0 grammes of sodium chloride dissolve in 100 grammes of water to create a saturated solution.