Question

2) the sum of first three terms of a GP is 16 and the sum of the next three terms is 128 , find the GP

3) divide 63 into three parts such that they are in GP and the product of the first and the second part is 3/4 th of the third part

Answer 1

Here's the answer..

Answer 2

Answer

0

crankybirds30

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Answer:

Let first term be a and common ratio be r.

So sum is a/(1−r)=x

For other series sum is a2/(1−r2)=y

So y/x2=(1−r)/(1+r)

So by componendo and dividendo

r=(x2−y)/(x2+y)