Question

2.The sum of the digits of a two digit number is10. If the digits are reversed , then the

new number is 36 more than the original number. Identify the two digit number.​

Answer 1

Answer:

Let the two-digit number be 10x + y.

Now, according to the question,

x + y = 10 ...(i)

and (x+10y)+36=(y+10x)

=> −9y+9x=36

=> −y+x=4 ...(ii)

On adding Eqs. (i) and (ii), we get

2x = 14 = x = 7

Therefore, x = 7 and y = 3

Therefore, Required number is 73.

Answer 2

Answer :

[ Given ]

The sum of two-digit = 10

Then suppose first digit = x

And second digit = y

Then the equation found x + y = 10

Now interchanging the number is decreased by 36

(10x + y) = (10y - x) -36

Then 10x - x + y - 10y = -36

9x - 9y = -36

Then all are divided by 9

So second equation found => x - y = -4

Add first and second equation

x + y = 10

+ x - y = 4

=> 2x = 6

then x = 3

Now First equation = 3 + y = 10

y = 10-3 = 7

y =7

Then original number = (10x + y)

10 x 3 + 7

=> 37 Answer √√