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The total power content of an AM signal is
3000 W. For 100% modulation, the power of
CW and that of each side band are,
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Answered by
1
Step-by-step explanation:
Given The total power content of an AM signal is 3000 W. For 100% modulation, the power of CW and that of each side band are,
- Now total power content P1 = 3000 W
- So converting 100% modulation we get μ = 1
- So power transmitted by the carrier wave will be P2
- So we have P1 = P2 (1 + μ^2 / 2)
- 3000 = P2 (1 + 1^2 / 2)
- Or 3/2 P2 = 3000
- Or P2 = 2000 W
- Now total power = side band + carrier wave
- 3000 = side band + 2000
- Or side band = 3000 – 2000
- Or side band = 1000 W
- Therefore power of each side band = 1000 W
Reference link will be
https://brainly.in/question/6866246
Answered by
0
Answer:
1000W will be the answer
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