Math, asked by chandrapavanyatam, 7 months ago

.2
The total power content of an AM signal is
3000 W. For 100% modulation, the power of
CW and that of each side band are,​

Answers

Answered by knjroopa
1

Step-by-step explanation:

Given The total power content of an AM signal is  3000 W. For 100% modulation, the power of  CW and that of each side band are,

  • Now total power content P1 = 3000 W
  • So converting 100% modulation we get μ = 1
  • So power transmitted by the carrier wave will be P2
  •      So we have P1 = P2 (1 + μ^2 / 2)
  •                       3000 = P2 (1 + 1^2 / 2)
  •                   Or 3/2 P2 = 3000
  •                   Or P2 = 2000 W
  • Now total power = side band + carrier wave
  •               3000 = side band + 2000
  •      Or side band = 3000 – 2000
  •   Or side band = 1000 W
  • Therefore power of each side band = 1000 W

Reference link will be

https://brainly.in/question/6866246

Answered by shahanaaz90
0

Answer:

1000W will be the answer

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