Question

2. The triangular side walls of a flyover have been used for advertisements. The sides
of the walls are 122 m, 22 m and 120 m (see Fig. 12.9). The advertisements yield an
earning of 5000 per m² per year. A company hired one of its walls for 3 months.
How much rent did it pay?
2
122m
22m
120m​

Answer 1

Answer:

In △ABC

a=122m,b=22m,c=120m

s= a+b+c/2 =122+22+120/2=132m

ar△ABC= √s(s−a)(s−b)(s−c)

= √132(132−122)(132−23)(132−120)

= √132×10×110×12

= √132×10×11×10×12

= √(132) ²×(10) ²

=132×10=1320 m ²

Rent per year = Rs. 5000

Rent of 1 m²per month = Rs. 5000/12

Rent of 1 m ²for 3 months=Rs. (3×5000)/12

Rent of 1320 m

2

for 3 months=Rs. ( 3×5000×1320)/2

= Rs.16,500,000

Step by step explanation:

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Answer 2

Answer:

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