Question

2. Three times the smallest of three consecutive odd integers decreased by 7 equals twice the largest number. Find the numbers.

Answer 1

Let the three consecutive odd number be x,x + 2, x + 4.

It is given that 3 times the smallest of 3 consecutive odd numbers decreased by 7 equals twice the largest one.

3x - 7 = 2(x + 4)

3x - 7 = 2x + 8

3x = 2x + 15

3x - 2x = 15

x = 15

x + 2 = 11 + 2 = 17

x + 4 = 11  + 4 = 19

Therefore the numbers = 15,17,19.