(-25)^3+10+15^3 Evaluate this by using suitable identity
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(103)
3
=(100+3)
3
Using, (a+b)
3
=a
3
+b
3
+3ab(a+b)
=(100)
3
+3
3
+3(100)(3)(100+3)
=1000000+27+900(100+3)
=1000000+27+90000+2700
=1092727
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