Question

2. To 50 ml of 0.1 N Na2CO3 solution 150 ml of water is added.

calculate the normality of the resultant solution.

​

Answer 1

Answer:

n-factor far Na  

2

​  

CO  

3

​  

 =2

∵ The n-factor of such salts is defined as the number of moles of electrons exchanged (lost or gained) by one mole of the salt. And there is the exchange of 2 electrons so its n factor is 2

Therefore, Normality = n-fator × molarity

Molarity =  

2

0.2

​  

 =0.1 M

Hence, the correct option is C

Explanation: