Question

[(2) to the power-1 + (4) to the power -1+(3) to the power-1] to the power -1​

Answer 1

Answer:

(2^-1+4^-1+3^-1)^-1

wait I will attach file

Answer 2

Answer:

$\boxed{ = \frac{12}{13}}$

Step-by-step explanation:

$=> [2^{-1}+4^{-1}+3^{-1}]^{-1} \\\\ => [\frac{1}{2}+\frac{1}{4}+\frac{1}{3}]^{-1} \\\\ => [\frac{1}{2} \times \frac{6}{6} + \frac{1}{4} \times \frac{3}{3} +\frac{1}{3} \times \frac{4}{4}]^{-1} \\\\ =>[\frac{6}{12}+\frac{3}{12}+\frac{4}{12}]^{-1} \\\\ =>[\frac{6+3+4}{12} ]^{-1} \\\\ =>[\frac{13}{12} ]^{-1} \\\\ => \frac{12}{13} \\ ----------- \\ \\ a^{-n} =\frac{1}{a^n}$