2 trains start from P and Q respectively and travel towards each other at a speed of 50km/hr and 40km/hr respectively..by the time they meet the 1st train has travelled 100km more than the second train.the distance between P andQ is???
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Let distance between P and Q = x km.
Suppose the two trains meet after y km.
By the time they meet the 1st train has traveled 100 km more than the second train.
==> y = (x - y) + 100.
==> y = x - y + 100
==> 2y = x + 100
==> y = (x + 100)/2
P and Q travel towards each other at a speed of 50 km/hr and 40 km/hr.
==> (y/50) = (x - y)/40
==> 40y = 50(x - y)
==> 40y = 50x - 50y
==> 40y + 50y = 50x
==> 90y = 50x
==> 90(x + 100)/2 = 50x
==> 90x + 9000 = 100x
==> x = 900.
The distance between P and Q is 900 km.
#BeBrainly.
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