2. Two angles of a triangle are equal and the third angle is 70º. Find the measure of equal angle
3. One of the acute angles of a right triangle is 58º. Find the measure of the other acute angles.
Answers
2.Let the measure of each equal angle be x,
So, first equal angle = other ( second ) equal angle.
∴ x = other equal angle
Third angle = 70°
sum of all angles of a triangle is 180°
x + x + 70° = 180°
2x + 70° = 180°
2x + 70° - 70° = 180° - 70°
2x = 110°
2x / 2 = 110 / 2
x = 55°
Therefore measure of each other two equal angles is 55°.
3.measure of acute angle= 58°=m1
let right angle be m2
and angle to be found= m3
m1+m2+m3= 180° (angle sum property of ∆)
58+90+m3=180
m3=180-58-90
m3=180-148
m3= 32
third angle would be 32°
hope it helped u(☆^ー^☆)Gd luck
plzzz mark brainliest tyvm!!!!
Answer:
2. 55°
3. 32°
Step-by-step explanation:
2.
=> Let all the angles of triangles as
L¹, L² and L³
L³=70°
Let L¹=L²=x
L¹+L²+L³= 180° ( Angle Sum Property)
x+x+70°= 180°
2x=180°-70°
2x=110°
x=110/2
=55°
3.
In a right triangle
one angle is 90°
second angle is 58°
third angle is ?
90°+58°+?=180° (angle sum property)
148°+?=180°
?=180°-148°
?= 32°
Hope You Understand it.