Question

2 unbiased coins are tossed simultaneously find the probability of getting

2 heads

At least on head

At most one head

Answer 1

Answer:

3/4 and 1/2

Step-by-step explanation:

Let S be the ample space

{HH,TT,HT,TH}

n(S)=4

Let A be the event such that at least one head is on the coin

A{HH,HT,TH}

n(A)=3

P(A)=n(A)/n(S)=3/4

Let B be the event such that at most one head is on the coin

B{HT,TH}

n(B)=2

P(B)=n(B)/n(P)=2/4=1/2