Question

2 under root 3 x square plus x minus 5 under root 3

Answer 1

$\textbf{Answer :}$

$Now, \\ \\ 2 \sqrt{3} \: {x}^{2} + x - 5 \sqrt{3} \\ \\ = 2 \sqrt{3} \: {x}^{2} + 6x - 5x - 5 \sqrt{3} \\ \\ = 2 \sqrt{3} \: x(x + \sqrt{3} ) - 5(x + \sqrt{3} ) \\ \\ = (x + \sqrt{3} )(2 \sqrt{3} \: x - 5),\\ \\ which \: \: is \: \: the \: \: required \\ factorization.$

#$\textbf{MarkAsBrainliest}$

Answer 2

Hey!!!...Here is ur answer

$2 \sqrt{3} {x}^{2} + x - 5 \sqrt{3} \\ \\ = 2 \sqrt{3} {x}^{2} + 6x - 5x - 5 \sqrt{3} \\ \\ = 2 \sqrt{3} x(x + \sqrt{3} ) - 5(x + \sqrt{3} ) \\ \\ = (x + \sqrt{3} )(2 \sqrt{3} x - 5)$

Hope it will help you