Question

2. Use the Factor Theorem to determine whether g(x) is a factor of p(x) in each of the
following cases : p(x) = x^3-4+x+6, g(x)=x-3
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Answer 1

Answer:

Step-by-step explanation:

p(x) = x³-4x²+x+6,

g(x)=x-3

If g(x)=0 or x-3=0

Then x=3

If g(x) is factor of p(x)

Then by factor theorem g(3)=0

Now g(3)=3³-4*3²+3+6

=27-4*9+3+6

=36-36

=0

Hence g(3)=0

Thus g(x) =x-3 is  a factor of p(x)