2. Value of sec 26" - cot 64" is
(a) 1
(b)-1
(c) 0
(d) 2
plz give the correct ans
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Answer:
We have,
sec
2
26
o
−cot
2
64
o
=sec
2
26
o
−cot
2
(90
o
−26
o
)
=sec
2
26
o
−tan
2
26
o
(∴sec
2
θ−tan
2
A=1)
=1
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