2 vectors p and q as sum of 18 and their resultant is 12 .The resultant is perpendicular to smaller of two vector find the value of p and q and angle between them
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Answer:
The value of p is 5 and q is 13
Explanation:
According to the problem the sum of two vectors
p+q= 18..(i)
The resultant of two vectors:
√p^2+q^2+2pqcosθ = 12
p^2+q^2+2pqcosθ = 144,...(ii)
Now the angle by the resultant vector is
qsinθ/p+qcosθ= tan 90 degree
p+qcosθ= 0
qcosθ= -p
now put the value in (ii)
q^2- p^2=144
(p+q)(q-p)= 144
18(q-p)=144
(q-p)= 8...(iii)
now by adding (i) and(iii)
p+q+q-p= 18+8
2q= 26
q= 13
now put it on (i)
p= 5
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