Math, asked by Greeshmabalasani, 6 months ago

2. verify that 1, 2 and 3 are the Zeros of
the Cubic polynomials. p(x) = -6x² + 1x-
6 and then verify the relationship between the
Zeros and the coefficients.​

Answers

Answered by pradnyakatare
2

Step-by-step explanation:

p(1)= -6(1)²+1(1)-6

p(1)= -6+1-6= -11

Since, p(1) ≠ 0,

1 is not a zero of polynomial.

p(2)= -6(2)²+1(2)-6

p(2)= -24+2-6= -28

Since p(2) ≠ 0,

2 is not a zero of polynomial.

p(3)= -6(3)²+1(3)-6

p(3)= -54+3-6= -57

3 is also not a zero of polynomial.

Non of these are zeroes of polynomial and it is not a cubic polynomial btw.

Hope it helps!❤️

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