2. verify that 1, 2 and 3 are the Zeros of
the Cubic polynomials. p(x) = -6x² + 1x-
6 and then verify the relationship between the
Zeros and the coefficients.
Answers
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Step-by-step explanation:
p(1)= -6(1)²+1(1)-6
p(1)= -6+1-6= -11
Since, p(1) ≠ 0,
1 is not a zero of polynomial.
p(2)= -6(2)²+1(2)-6
p(2)= -24+2-6= -28
Since p(2) ≠ 0,
2 is not a zero of polynomial.
p(3)= -6(3)²+1(3)-6
p(3)= -54+3-6= -57
3 is also not a zero of polynomial.
Non of these are zeroes of polynomial and it is not a cubic polynomial btw.
Hope it helps!❤️
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