Question

2 water taps together can fill a tank in one hour and twelve minutes. The tap
of smaller diameter takes 1 hour more than the larger one to fill the tank
separately. Find the time in which each tap can separately fill the tank.​

Answer 1

Answer:

Step-by-step explanation:

let the time taken by larger tap be x

And by smaller6p tap be [x+10]hrs

therefore....

larger tap can fill = 1/x par of the tank

smaller tap can fill = 1/[x +10] part of tank

TOGETHER THEY CAN COMPLETELY FILL THE TANK IN 9×3/8=75/8

1/x+10 + 1/x =1/75 upon 8

x+x+10/x*2+10x = 75/8

2x+10/x*2+10x = 8/75

HERE....,

150x+750=8x*2+80x

8x*2+80x-150x-750=0

8x*2+70x-750=0

4x(x-5)+25(x+15)=0

4x+25=0 OR x-15=0

x=-25/4 OR x=15

Since the time can't be in negative.

THEREFORE, x is not equal to-25/4,

so the answer is........

x=15

THANKU!!!!!!