Question

2. What is the value of k, if the roots of kx2 +24x +16=0 are real and equal?
(A) 9
(B) -9
(C) 25
(D) – 25​

Answer 1

Answer:

real and equal?

(A) 9

(B) -9

(C) 25

(D) – 25

Answer 2

Answer:

(B) -9

Step-by-step explanation:

(B) -9

kx^2+24x+16=0

a=k, B=24, c=16

b^2-4ac=(24)^2-4×k×16

=576-64k

But roots are real and equal

b^2-4ac=0

576-64k=0

-64k=576

-k=576/64

-k=9

-k=-9