Math, asked by ebuengrinoa614, 2 months ago

2. When the length of a rectangle is three times its width and its perimeter is 48
cm, what is its width?
a. 8cm
b. 6cm c. 12cm d. 10cm​

Answers

Answered by firozpasha999
0

Answer:

So, the perimeter of any rectangle is given by adding the length twice and the width twice:

P=L+W+L+W

In our particular case the length is 3 times the width:

L=3×W

Substituting that, and the 48 centimeters we know the perimeter to be into the first equation, we get:

48=3×W+W+3×W+W

48=8×W

W==488

W=6

So, if the width is 6, the length is:

L=3×W=3×6=18

Now, the area of any rectangle is given by multiplying the length and the width:

A=L×W

In our case L=18 and W=6, so:

A=18×6=108

Also, remember to "multiply" the units. In this case centimeter times centimeter gives us centimeter2 or cm2

So the area is 108cm2

Answered by kusumrawat041
2

Step-by-step explanation:

Let the width be X

so the length- 3X

Perimeter-48 cm

So,Perimeter of rectangle- 2(length+width)

48cm - 2(3X+X)

48cm-6X+2X

48cm-8X

48/8-x

6cm- width

Answer: 6cm

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