Question

2. Whose perfect square should be added to the sum of the greatest three-digit
prime number and the smallest two-digit prime number, so that the resultant
number is perfect square of 32?
(2019)
(1) 2 (2) 3 (3) 4 (4) 6
11
hole​

Answer 1

Answer:

± 4

Step-by-step explanation:

Given whose perfect square should be added to the sum of the greatest three digit prime number and the smallest two digit prime number so that the resultant number is perfect square of 32​

Let p be the required number.

We know that greatest three digit prime number is 997

                  smallest two digit prime number is 11

Now according to question we have

           p^2 + 997 + 11 = 32^2

         p^2 + 1008 = 1024

         p^2 = 1024 - 1008

         p^2 = 16

        p = ± 4

Please Mark my answer as brainlist