Question

2 wires a and b are of same metal for same area of cressection and have their lengths in the ratio of 2:1 what will be the ratio of current flowing through them when same potential difference is applied acress the length of each of them.

Answer 1

When length is double then resistance is
double
So 2×resistance of a=resistance of b
Let current flowing in a be I1 and in b be I2
then
I1=2R/V
and I2=R/V
so
I1/I2= 2R/V/R/V
=2/1
So required ratio is 2:1