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Without factorization find the nature of the roots of the quadratic equation
4x^2-12x + 9=0
Answers
Answered by
0
Answer:
real and distinct
Step-by-step explanation:
Given : 4x² - 12x - 9 = 0 . Therefore, root of the given equation 4x² - 12x - 9 = 0 are real and distinct. Hence, nature of roots of the quadratic equation 4x²− 12x − 9 = 0 are real and distinct
Answered by
1
Answer:
The roots for the given quadratic equation are
x = 3/2 , 3/2
The roots are real and equal
Step-by-step explanation:
By using the Quadratic equation formula
-b +/- √b^2 - 4ac /2a
= 12 +/- √ 12^2 - 4(4)(9) /2(4)
= 12 +/- √ 144-144 /8
= 12 +/- 0 / 8
= 12 / 8
= 3/2
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