2 women and 5 men can together finish an embroidery work in 4 days while 3 women and 6 men can finish it in 3 days .Find the time taken by 1 women alone to finish the work , and also that taken by 1 man alone.
Answers
Answer:
Let 1 woman do the work in x days.
Let 1 man do the work in y days.
Therefore,
1 woman's one day's work=1/x part
Therefore, 2 women 1 day's work =2/x part
1 man's 1 day's work = 1/y part
Therefore,
5 men 1 day's work=5/y part
By question,
2/x +5/y =1/4
2 *1/x +5*1/y=1/4
2u +5v =1/4 [Taken 1/x =u, 1/y=v]
8u +20v=1-------i
Similarly,
3/x +6/y=1/3
3u+6v=1/3 [Taken 1/x =u, 1/y=v]
9u +18 v=1---------ii
By elimination,
i *9---72u +180v=9------iii
ii *8--72u +144v=8------iv
- - -(as the sign changes)
iii -iv -------- 36v=1
v =1/36
Putting 1/36 in eqn ii, we get,
9u+18*1/36=1
9u *1/2=1
9u=1-1/2
9u=2-1/1
u=1/18
Therefore,
1/x=u
1/x=1/18
x=18
And,
1/y=v
1/y=1/36
y=36.
Therefore one woman takes 18 days and one man takes 36 days to finish the work...
HOPE IT HELPS YOU
Answer:
Number of days taken by a woman = 18 days
Number of days taken by a man= 36 days
Step-by-step explanation:
