Math, asked by shalin4567, 1 month ago

2 women and 5men can together finish an embroidery work in 4 days while 3 women and 6men can finish it 8n 3days .find the time taken by 1 women alone to finish the work and also that taken by 1 man alone​

Answers

Answered by bhairavi14
0

Answer:

Time taken by 1 woman alone to finish the work: 18 days, and also that taken by 1 man alone: 36 days

Step-by-step explaination:

Let the work done by man and woman per day be x and y respectively.

When the work is completed in 4 days

Since 5 men and 2 women complete the work in 4 days

therefore work done by 5 men and 2 women in 1 day = 1/4

∴5x+2y= 1/4

⟶eq ^n 1

When the work is completed in 3 days

Since 6 men and 3 women complete the work in 3 days

therefore work done by 6 men and 3 women in 1 day = 1/3

∴6x+3y= 1/3

⟶eq ^n 2

Multiplying by 3 in eq ^n 1we get

⇒15x+6y= 3/4

⟶eq ^n 3

Multiplying by 2 in eq ^n 2 ,we get

⇒12x+6y= 2/3

⟶eq ^n4

On subtracting eq ^n 4 from eq ^n 3 , we get

⇒15x+6y−12x−6y= 3/4 - 2/3

⇒3x= 1/12

⇒x= 1/36

On substituting the value of x in eq ^n 2 , we get

⇒6× 1/36 +3y= 1/3

⇒3y= 1/3 - 1/6

⇒y= 1/18

Thus,

work done by 1 man in 1 day = 1/36 days

∴ Time taken by 1 man alone to finish the work =36 days

work done by 1 woman in 1 day = 1/18 days

∴ Time taken by 1 woman alone to finish the work =18 days

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