Triangle ABC and triangle DEF are equilateral triangles and A (triangle ABC ) : A (triangle DEF) = 1: 4 ..IF BC = 4CM WHAT IS EF?
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Answer:
∆ABC and ∆DEF are equilateral triangles.
so, angle A = Angle C = Angle D = 60°
and
Angel D = Angle E = Angle F = 60°
hence ∆ABC and ∆DEF are similar triangles
AB/DE = BC/EF = CA/FD and Area of ∆ABC / Area of ∆ DEF = (AB/DE)² = (BC/EF)² = (CA/FD)²
Hence, A (∆ABC)/ A (∆DEF) = 1/4 = (1/√16)²
so, AB/DE = BC/EF = CA/FD = (1/√16)²
BC/EF = 1/√16
EF=BC√16
=4√16 [BC = 4cm]
also can be 2√8 .
Step-by-step explanation:
hope this answer helps you take care!
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