Question

2. Write a Pythagorean triplet whose one member is.
(i) 6
(ii) 14
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Answer 1

Answer:

Step-by-step explanation:

Squares and Square Roots. Write a Pytagorean triplet whose one member is. Thus the required Pythagorean triplet is 6,8,10. Thus the required Pythagorean triplet is 14,48,50

Answer 2

hi mate here is your answer

Step-by-step explanation

let 2n=6      n=3

n^2 -1=3^2-1=8

n^2 +1=3^2+1=10

6,8,10

next let 2n=14      n=7

n^2-1=7^2-1=48

n^2+1=7^2+1=50

14,48,50

i hope you understand it