Question

(2^x-1)+(2^x+1)=320​

Answer 1

(2^x-1)+(2^x+1)=320. .....[m^a+m^b=m^a+b]

2^x/2 + 2×2x =320

2^x. [1/2 + 2] =320

2^x.[5/2] = 320

2^x = 320 × 2/5

2^x=64×2

2^x=2^6 ×2

2^x=2^7. ...........[Hence solved]

Answer 2

Step-by-step explanation:

$\bf \underline{Given-}$

$\sf{ {2}^{x - 1} + {2}^{x + 1} = 320 }$

$\bf \underline{To \: find-}$

$\textsf{the value of x = ?}$

$\bf \underline{Solution-}$

$\textsf{We have,}$

$\sf{ {2}^{x +1} + {2}^{x - 1} = 320 }$

$\sf{ \Rightarrow \: {2}^{x} \: . \: {2}^{1} + {2}^{x} \: . \: {2}^{ - 1} = 320}$

$\sf{ \Rightarrow \: {2}^{x} \bigg(2 + \frac{1}{2} \bigg) = 320 }$

$\sf{ \Rightarrow \: {2}^{x} \times \frac{5}{2} = 320 }$

$\sf{ \Rightarrow \: {2}^{x} = \frac{320 \times 2}{5} }$

$\sf{ \Rightarrow \: {2}^{x} = \cancel{\frac{ {640}^{128} }{5} } }$

$\sf{ \Rightarrow \: {2}^{x} = 128}$

$\sf{ \Rightarrow \: {2}^{x} = {2}^{7} }$

$\sf{ \Rightarrow \: x =7}$

$\bf \underline{Answer-}$

$\bf{ \underline{Hence, the \: value \: of \: x \: is \: 7.}}$