Math, asked by Thushita, 1 year ago

2(x-1)+3y=4. Prove this equation in four solutions

Answers

Answered by suryanshverma29
5

2x-y=4

(i) put x=0

then,

2(0)-y=4

y=-4   

(ii) put x=1

then,

2(1)-y=4

y=-2

(iii) put x=2

then,

2(2)-y=4

y=0

(iv) put x=3

then,

2(3)-y=4

y=2

Hence the four solutions are,

x=0,y=-4

x=1,y=-2

x=2,y=0

x=3,y=2

Answered by AadilPradhan
3

The four solutions are (0,2), (1,4/3), (2, 2/3), (3,0).

Given:

2(x-1)+3y=4

To find:

Four solutions for this equation

Solution:

For finding 4 different solutions, we will take up four values of x starting form o and will calculate y through it and hence, the equation will be proved and we will get 4 solutions

Let x = 0;

2(x-1) + 3y = 4

2(0-1) + 3y = 4

-2 + 3y = 4

3y = 4+2

3y = 6

y = 6/3

y = 2

Let x = 1;

2(x-1) + 3y = 4

2(1-1) + 3y = 4

2*0 + 3y = 4

3y = 4

y = 4/3

Let x = 2

2(x-1) + 3y = 4

2(2-1) + 3y = 4

2*1 + 3y = 4

2 + 3y = 4

3y = 4-2

3y = 2

y = 2/3

Let x = 3;

2(x-1) + 3y = 4

2(3-1) + 3y = 4

2*2 + 3y = 4

4 + 3y = 4

3y = 4-4

3y = 0

y = 0

So, the four solutions are (0,2), (1,4/3), (2, 2/3), (3,0).

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