Math, asked by starsoul786, 9 months ago

2^x+1=4^x-3 solve the following equation​

Answers

Answered by ToxicEgo
0

Solution:

2^x+1=4^x-3

→2^x+1=(2) ^2(x-3)

→2^x+1=2^2x-6..... (a^3+x= a^4+x then 3+x=4+x)

→x+1=2x-6

→ x-2x=-6-1

→ -x= -7

→ x=7

Answered by Anonymous
82

\rule{300}3

\huge{\blue{\fbox{\bold{\red{UR\:QUESTION}}}}}

\huge {\mathbf {\purple {Q.}}}}2^x+1=4^x-3 solve the following equation

\rule{300}3

\huge{\blue{\fbox{\bold{\red{UR\:ANSWER}}}}}

 \sf\implies 2^x+1=4^x-3

 \sf\implies  2^x+1=(2) ^2(x-3)

 \sf\implies 2^x+1=2^2x-6 .....a^3+x= a^4+x \:then\: 3+x=4+x

 \sf\implies x+1=2x-6

 \sf\implies  x-2x=-6-1

 \sf\implies -x= -7

 \sf\implies x=7

\sf{\blue{\fbox{\red{x=7}}}}

\rule{300}3

\tt\huge\red{\text{BE \:BRAINLY}}

\rule{300}3

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