2(x+1/x)²-7(x+1/x)+6=0
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Answered by
1
2(x^2+1+2x/x^2)-7(x+1/x)+6=0
2x^2+2+4x/x^2-7x-7/x+6=0
Taking LCM of x^2,x,1 is x^2
2x^2+2+4x-7x^2-7x+6x^2/x^2=0
x^2-3x+2=0*x^2
x^2-2x-x+2=0
x(x-2)-1(x-2)=0
(x-1)(x-2)=0
x=1,2
2x^2+2+4x/x^2-7x-7/x+6=0
Taking LCM of x^2,x,1 is x^2
2x^2+2+4x-7x^2-7x+6x^2/x^2=0
x^2-3x+2=0*x^2
x^2-2x-x+2=0
x(x-2)-1(x-2)=0
(x-1)(x-2)=0
x=1,2
Answered by
1
Let (x+1)/x =m...(1)
You will get
2m²-7m+6=0
solve this quadratic
then use the values of m in (1) to find x
You will get
2m²-7m+6=0
solve this quadratic
then use the values of m in (1) to find x
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