Question

2^x+13=4^x+2 then find the value of x?​

Answer 1

Answer:

2^x+13=4^x+2

4^x-2^x=11    Then  Log[4^x/2^x]=Log11 Then Log[2^ x]=Log11

x=Log11/Log2

Step-by-step explanation:  Use basic logarithmic properties.

Answer 2

Answer:

x= 9

Step-by-step explanation:

The Product Rule for Exponents: am * an = am + n.

To locate the made of numbers with the equal base, upload the exponents.

The Quotient Rule for Exponents: am / an = am–n.

To locate the quotient of numbers with the equal base, subtract the exponent of the denominator from the exponent of the numerator.

The Power Rule for Exponents: (am)n = am*n.

To increase various with an exponent to a electricity, multiply the exponent instances the electricity.

Negative Exponent Rule: x–n = 1/xn.

Invert the bottom to extrade a poor exponent right into a positive.

Zero Exponent Rule: x0 = 1, for .

Any non-0 wide variety raised to the zeroth electricity is 1.

2^x+13 = 2² ^(x+2)

2^x+13 =2^(2x+4)

Equalise the power as the base is now same :

x+ 13 = 2x +4

2x - x = 13 -4

x= 9

(#SPJ2)