(2(x^2+1)=5x please tell me the answer of this equation
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☛ { 2(x² + 1) } = 5x
☛ { 2x² + 2 } = 5x
☛ 2x² - 5x + 2 = 0
☛ 2x² - 4x - x + 2 = 0
☛ 2x ( x - 2) - 1 ( x - 2 ) = 0
☛ (x - 2)(2x - 1) = 0
x - 2 = 0 ; 2x - 1 = 0
x = 2 ; x = 1/2
So values that satisfy the equation are 2 and 1/2
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