Question

2(x-2) + 3(4x-1) = 0

Answer 1

Answer:

2(x-2) +3(4x-1) =0

2x-4+12x-3=0

14x-7=0

14x=0+7

14x=7

x=7/14

x=1/2

Answer 2

$\rm \implies2(x - 2) + 3(4x - 1) = 0$

$\rm \implies2x -4+ 12x - 3= 0$

$\rm \implies 14x - 7= 0$

$\rm \implies 14x = 7$

$\rm \implies x = \dfrac{7}{14}$

$\rm \implies x = \dfrac{1}{2}$

Answer : x = 1/2

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Verification of Answer :-

To verify our answer put x = 1/2 in 2(x-2) + 3(4x-1) = 0. If we get left hand side and right hand side equal then our answer is correct.

RHS = 0

LHS = 2(x-2) + 3(4x-1)

put x = 1/2 in LHS

$\rm \implies2( \frac{1}{2} - 2) + 3( \frac{4}{2}- 1)$

$\rm \implies2( \frac{1 - 4}{2} ) + 3( \frac{2}{1}- 1)$

$\rm \implies(2 \times \frac{ - 3}{2} )+( 3 \times 1)$

$\rm \implies(1 \times \frac{ - 3}{1} )+( 3 \times 1)$

$\rm \implies - 3 + 3$

$\rm \implies0$

Therefore , RHS = LHS

hence verified