Math, asked by krishaymanjunath, 4 months ago

Factorise: –64a³ –12a + 48a²

Answers

Answered by harshabhiraj14
1

(4a)³-3(1)²(4a)+3(1)(4a)²

suitable identities is x³-y³-y³-3x²y=(x-y)³

(1)³-(4a)³-3(1)²(4a)+3(1)(4a)²

=(1-4a)³

Answer:(1-4a)³

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