Factorise: –64a³ –12a + 48a²
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(4a)³-3(1)²(4a)+3(1)(4a)²
suitable identities is x³-y³-y³-3x²y=(x-y)³
(1)³-(4a)³-3(1)²(4a)+3(1)(4a)²
=(1-4a)³
Answer:(1-4a)³
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