√2 x^2 – 3x - 2√2 = 0
completing the square method pls
Answers
Answered by
1
Answer:
√2x^2-3x-2√2=0
=> √2x^2-4x+x-2√2=0
=> √2x(x-2√2)+1(x-2√2)=0
=> (x-2√2)(√2x+1)=0
=> x-2√2=0
=> x=2√2
√2x+1=0
=> √2x= -1
=> x= -1/√2= -√2/2
Similar questions