2^x+2^x+1=24then find the value of x
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2^x + 2^(x + 1) = 24
=> 2^x + [ ( 2^x ) × 2] = 24
=> 2^x [ 1 + ( 1 × 2)] = 24
=> 2^x(3) = 24
=> 2^x = 24/3
=> 2^x= 8
=> 2^x = 2^3
If bases are equal, powers are also equal,
x = 3
=> 2^x + [ ( 2^x ) × 2] = 24
=> 2^x [ 1 + ( 1 × 2)] = 24
=> 2^x(3) = 24
=> 2^x = 24/3
=> 2^x= 8
=> 2^x = 2^3
If bases are equal, powers are also equal,
x = 3
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