Math, asked by brij8281, 9 months ago

2-√x/2-x =√2/√2-√x find value of x​

Answers

Answered by Anonymous
1

Answer:

 \frac{2 -  \sqrt{x} }{2 - x}  =  \frac{ \sqrt{2} }{ \sqrt{2}  -  \sqrt{x} }  \\  \frac{2 -  \sqrt{x} }{2 - x}  =  \frac{ \sqrt{2}( \sqrt{2}   +  \sqrt{x})  }{( \sqrt{2}  -  \sqrt{x})( \sqrt{2}   +  \sqrt{x}) }  \\  \frac{2 -  \sqrt{x} }{2 - x}  =  \frac{ \sqrt{2}( \sqrt{2} +  \sqrt{x}  ) }{ { \sqrt{2 } }^{2}  -  { \sqrt{x} }^{2} }

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