Question

2^x-3×3^2x-8=36 find the value of x​

Answer 1

Answer:

2

x−3

×3

2x−8

=4×9

2

x−3

×3

2x−8

=2

2

×3

2

2

x−5

×3

2x−10

=1

x=5

as RHS is 1, the powers have to be zero on the LHS as anything raise to 0 is always 1

Thus x−5=0→x=5