2/x+3/y=13 and 5/x-4/y=-2 by cross multiplication method
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Given,
2/x + 3/y = 13 ----(1)
5/x - 4/y = -2 ------(2)
Let 1/x = a and 1/y = b , We get
2a+3b=13 -----(3)
5a-4b = -2 -----(4)
On solving (3) * 4 & (4) * 3, we get
8a + 12b = 52
15a - 12b = -6
----------------------
23a = 46
=> a = 2
Substitute the value of a in equation (3), we get
=> 4 + 3b = 13
=> 3b = 13 - 4
=> 3b = 9
=> b = 9/3
=> b = 3
But 1/x = a = 2 => x = 1/2
1/y = b = 3 => y = 1/3
Thus,
x = (1/2), y = (1/3)
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