Question

2^x+3^y=17;2^x+2-3^y-1=5

Answer 1

Answer:

let 2^x = t 

let 3 ^y = q 

q+t = 17 

q-t =3 

2q =20  when i add these both eqution 

q= 10 

put q in eqution q+ t = 17 

t= 7 

 now using log we can find x and y 

2^x = 10

xlog 2 = 1 

x= 1/log2 log 10 =1

as

7= 3^y

log 7 /log 3 =y means y = log 7 base 3 

HOPE IT HELPS.......