Math, asked by yashmandal45, 7 months ago

2/√x+3/√y=2 and 4/√x-9√y=-1 solve by elamating method​

Answers

Answered by Nisha69Rohan
0

The given equations have √x and √y as the variables which need to be found.

I took the terms of 1/√x and 1/√y as a and b respectively.

On doing this the equatios become

2a+3b = 4 and 4a- 3b = -1

Now marking them as equation 1 and 2 respectively we substitute the value of a from equation 1 into equation 2 we find the values of a and b as 1/2 and 1/3 respectively.

On equating the values of a with 1/x and b with 1/y respectively we get the values of x and y as

x = √2 and y =√3.

Please refer to given solution in the figure.

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Answered by ashauthiras
1

Answer:

let to be 1/√x=a

let to be 1/√y=b

2a+3b=2

4a+9b=-1

solve this equation by elimination method,

2a+3b=2*4

4a-9b=-1*2

8a+12b=8

8a-18b=-2

30b=10

b=10/30=1/3

2a+3b=2

2a+3*1/3=2

2a+1=2

2a=2-1

2a=1

a=1/2

Now, putting the value of a and b

1\√x=1/2

x=√2

1/√y=b

1/√y=1/3

y=√3

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