Question

2^x=3^y=6^then 1/x+1/y =

Answer 1

Answer:

2x=3y=6−z=k (Let)

So,

2=k1/x,

3=k1/yand

6=k−1/z

Since,

2×3=6

⟹k1/x×k1/y=k−1/z

⟹k1/x+1/y=k−1/z

Since k is not 0

⟹1/x+1/y=−1/z

1/x+1/y+1/z=0