Question

2/(x-4)=1/(x-3),not eqal to 3,4​

Answer 1

$\frac{2}{x - 4} = \frac{1}{x - 3} \\ \\ \frac{2}{x - 4} - \frac{1}{x - 3} = 0 \\ \\ \frac{2(x - 3) - 1(x - 4)}{(x - 4)(x - 3)} = 0 \\ \\ \frac{2x - 6 - x + 4}{ {x}^{2} - 3x - 4x + 12 } = 0 \\ \\ \frac{x - 2}{ {x}^{2} - 7x + 12} = 0 \\ \\ x - 2 = 0 ( {x}^{2} - 7x + 12) \\ \\ x - 2 = 0 \\ \\ \bf x = 2$