Question

2(x-5)+3(x-2)=8+7(x-4)​

Answer 1

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Answer 2

Answer:

2(x-5)+3(x-2)=8+7(x-4)

2x-10+3x-6=8+7x-28

By trasposing LHS to RHS

7x-2x-3x+8+6+10-28=0

5x-4=0

5x=4

X=4/5