Question

2 X + 5 upon 7 x 2 x minus 2 upon 5 find using the identity X*2+(a+b)x+ab​

Answer 1

$\huge\color{cyan}\boxed{\colorbox{black}{ANSWER ❤}}$

$\blue{(2x + \frac{5}{7} )(2x - \frac{2}{5} )}$

WE KNOW THAT:

$\red{(x + a)(x + b) = {x}^{2} + (a + b)x + ab }$

HERE,

$\purple{x = > 2x}$

$\purple{a = > \frac{5}{7} }$

$\purple{b = > \frac{ - 2}{5} }$

NOW PUT THE VALUES :

$\blue{ {(2x)}^{2} + ( \frac{5}{7} + \frac{ - 2}{5} )2x + (\frac{5}{7})( \frac{ - 2}{5} )}$

$\blue{4 {x}^{2} + ( \frac{25 - 14}{35} )2x - \frac{2}{7} }$

$\blue{4 {x}^{2} + ( \frac{11}{35} )2x - \frac{2}{7} }$

$\blue{4 {x}^{2} + \frac{22 x }{35} - \frac{2}{5} }$